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Proof step 11 from proof modzero-08 (previous step)

0 < i, i * j + j0 < i, abs(j0) < j, i * j + j0 ≤ 0 ⊦ i * j + j0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
abs(j0) < j, i * j + j0 < i, 0 < i, i * j + j0 < 0 ⊦ i * j + j0 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)