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Proof step 1 from proof mult-pos (conclusion)
⊦ 0 ≤ i ∧ 0 < j ∧ i1 < 0 → i * i1 ≠ j
System applied rule normalize
And obtained the following new goals
Proof step 2
:
i * i1 = j, 0 < j, i1 < 0, 0 ≤ i ⊦
Rule argument
Additional information