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Proof step 23 from proof noeth-modlep (previous step)

0 < j2, j0 < j2, i0 < i, j0 < j, 0 < j, j ≤ j2, 0 ≤ j0, j * i ≤ j * i0 + j0, ∀ j0, j, i, i0. j0 < abs(j) ∧ abs(j) < j2 ∧ abs(j) * i ≤ abs(j) * i0 + j0 ∧ 0 ≤ j0 → i ≤ i0 ⊦

User applied rule all left

And obtained the following new goals

Proof step 24:
0 < j, j0 < j, i0 < i, j0 < j2, 0 < j2, j * i ≤ j * i0 + j0, 0 ≤ j0, j ≤ j2, j0 < abs(j - 1) ∧ abs(j - 1) < j2 ∧ abs(j - 1) * i ≤ abs(j - 1) * i0 + j0 ∧ 0 ≤ j0 → i ≤ i0 ⊦

Rule argument

pos: left 9 terms: j0, j - 1, i, i0 abort: F discard: T computed: F

Additional information

Used terms: j0, j - 1, i, i0