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Proof step 25 from proof noeth-modlep (previous step)

0 < j2, j0 < j2, i0 < i, j0 < j, 0 < j, j ≤ j2, 0 ≤ j0, j * i ≤ j * i0 + j0 ⊦ j0 + 1 < j ∧ (j - 1) * i ≤ (j - 1) * i0 + j0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 26:
j = i1 + 1, 0 < j, j0 < j, i0 < i, j0 < j2, 0 < j2, j * i ≤ j * i0 + j0, 0 ≤ j0, j ≤ j2 ⊦ j0 + 1 < j ∧ i1 * i ≤ i1 * i0 + j0

Rule argument

spec: int-abs name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, 1, i1]

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, 1, i1