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Proof step 1 from proof one (conclusion)

⊦ 1 * i = i

User applied rule apply lemma

And obtained the following new goals

Proof step 2:
⊦ (i + 1) * j = i * j + j

Rule argument

spec: <toplevel> name: succ-lsplit seq: ⊦ (i + 1) * j = i * j + j subst: [i, j] → [0, i]

Additional information

Used simplifier rules: zero-left: ⊦ 0 * i = 0;%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2% ⊦ i + 0 = i; (s) Used terms: 0, i