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Proof step 2 from proof ple-neg (previous step)

j0 < j, j < 0, i < 0, i0 ≤ i ⊦ i * j ≤ i0 * j0

User applied rule apply lemma

And obtained the following new goals

Proof step 3:
i < 0, j < 0, i0 ≤ i, j0 < j ⊦ i * j < i0 * j0

Rule argument

spec: <toplevel> name: pls-neg seq: i < 0, j < 0, i0 ≤ i, j0 < j ⊦ i * j < i0 * j0 subst: [i, j, i0, j0] → [i, j, i0, j0]

Additional information

Used simplifier rules: ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i < j → ¬ j < i; (s) Used terms: i, j, i0, j0