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Proof step 2 from proof pls-neg (previous step)

j0 < j, j < 0, i < 0, i0 ≤ i ⊦ i * j < i0 * j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j0 < 0, i0 < 0, j0 < j, j < 0, i < 0, j0 + 1 < 0, i0 * j0 ≤ i * j, i0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i +1 = i + 1; (s)%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1% ⊦ i < j ↔ ¬ j ≤ i; (ss)