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Proof step 2 from proof pls-pos (previous step)

j < j0, 0 < j, 0 < i, i ≤ i0 ⊦ i * j < i0 * j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < i, 0 < j, j < j0, 0 < i0, 0 < j0, 1 < j0, i ≤ i0, i0 * j0 ≤ i * j ⊦

Rule argument

Additional information

Used simplifier rules: forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1% ⊦ i < j ↔ ¬ j ≤ i; (ss)