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Proof step 2 from proof pnls-negpos (previous step)

i0 * j0 < i * j, i0 ≤ 0, 0 ≤ j0, j0 ≤ j, i ≤ i0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i0 * j0 < i * j, i ≤ i0, j0 ≤ j, 0 ≤ j0, i0 ≤ 0, i ≤ 0, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s)%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs