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Proof step 6 from proof short-mult-max (previous step)

i < 256, 0 < i, 65536 < 256 * j, 0 < j, 65536 ≤ i * j, j ≤ 256, 0 ≤ j ⊦ i = 0

User applied rule cut formula

And obtained the following new goals

Proof step 7:
65536 = 256 * 256, 0 < j, 65536 < 256 * j, 0 < i, i < 256, 0 ≤ j, j ≤ 256, 65536 ≤ i * j ⊦ i = 0

Rule argument

fma: 65536 = 256 * 256

Additional information

Used formulas: 65536 = 256 * 256