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Proof step 15 from proof square-eq (previous step)

i * i = j * j, abs(j * j) < abs(i) * abs(i), abs(j) < abs(i) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: abs-eqall seq: ⊦ abs(i * j) = abs(i) * abs(j) subst: [j, i] → [i, i] flags: <rotated> <all paths>

Additional information

Used terms: i, i