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Proof step 18 from proof square-eq (previous step)

abs(i) = abs(j) ⊦ i * i = j * j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 19:
⊦ ¬ j < 0 → abs(j) = j
Proof step 20:
abs(i) = abs(j), i < 0 ⊦ i * i = j * j
Proof step 26:
i = abs(j) ⊦ i * i = j * j, i < 0

Rule argument

spec: int-abs name: Abs-pos seq: ⊦ ¬ j < 0 → abs(j) = j subst: [j] → [i] flags: <all paths>

Additional information

Used terms: i