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Proof step 23 from proof square-le-04 (previous step)

j + j * j < i + i * i, i ≤ j, 0 ≤ j, 0 ≤ i, i + i * i ≤ i + j * j ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 24:
j + j * j < i + i * i, i + i * i ≤ i + j * j, 0 ≤ i, 0 ≤ j, i ≤ j ⊦ j + j * j < i + j * j

Rule argument

fma: j + j * j < i + j * j

Additional information

Used simplifier rules: ⊦ i + j < i + i0 ↔ j < i0; (s)% ⊦ i ≤ j → (j < i ↔ false); (as)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: j + j * j < i + j * j