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Proof step 2 from proof square-lez-01 (previous step)

i * i ≤ 0 ⊦ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i * j ≤ 0 ↔ i = 0 ∨ j = 0 ∨ 0 ≤ i ∧ j ≤ 0 ∨ i ≤ 0 ∧ 0 ≤ j
Proof step 4:
i = 0 ∨ i = 0 ∨ 0 ≤ i ∧ i ≤ 0 ∨ i ≤ 0 ∧ 0 ≤ i ⊦ i = 0

Rule argument

spec: <toplevel> name: zero-le-case seq: ⊦ i * j ≤ 0 ↔ i = 0 ∨ j = 0 ∨ 0 ≤ i ∧ j ≤ 0 ∨ i ≤ 0 ∧ 0 ≤ j subst: [j, i] → [i, i] flags: <all paths>

Additional information

Used terms: i, i