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Proof step 5 from proof square-lez-01 (previous step)

0 < i ∧ i < 0 ∨ i < 0 ∧ 0 < i ⊦ i = 0

Heuristic cut applied rule cut formula

And closed the goal!

Rule argument

fma: 0 < i

Additional information

Used simplifier rules: ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)% ⊦ i < j → ¬ j < i; (s) Used formulas: 0 < i