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Proof step 6 from proof square-ls-02 (previous step)

i * i + i < j * j + j, 0 ≤ i, 0 ≤ j, j + j * j ≤ j + i * i ⊦ i < j

User applied rule cut formula

And obtained the following new goals

Proof step 7:
i * i + i < j * j + j, j + j * j ≤ j + i * i, 0 ≤ j, 0 ≤ i ⊦ i < j, i + i * i < j + i * i

Rule argument

fma: i + i * i < j + i * i

Additional information

Used simplifier rules: ⊦ i + j < i + i0 ↔ j < i0; (s)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i + i * i < j + i * i