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Proof step 7 from proof square-ls (
previous step
)
i * i < j * j ⊦ j = 0, abs(i) < abs(j), abs(j) ≤ abs(i)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 8
:
⊦ i < j ↔ ¬ j ≤ i
Rule argument
spec: int-abs name: lels seq: ⊦ i < j ↔ ¬ j ≤ i subst: [j, i] → [abs(j), abs(i)] flags: <all paths>
Additional information
Used terms: abs(j), abs(i)