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Proof step 9 from proof square-ls (previous step)

i * i < j * j, abs(j) * abs(j) ≤ abs(i) * abs(i) ⊦ abs(i) < abs(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ abs(i * j) = abs(i) * abs(j)
Proof step 11:
i * i < j * j, abs(j * j) ≤ abs(i) * abs(i) ⊦ abs(i) < abs(j)

Rule argument

spec: <toplevel> name: abs-eqall seq: ⊦ abs(i * j) = abs(i) * abs(j) subst: [j, i] → [j, j] flags: <rotated> <all paths>

Additional information

Used terms: j, j