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Proof step 8 from proof square-one-le (previous step)

i + 1 = 0, 1 < i * i ⊦ i = 0, i = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ i + j = 0 ↔ i = ~ j

Rule argument

spec: int-abs name: rew-eqzero seq: ⊦ i + j = 0 ↔ i = ~ j subst: [j, i] → [1, i] flags: <all paths>

Additional information

Used simplifier rules: associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i; Used terms: 1, i