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Proof step 2 from proof succ-lsplit (previous step)

∀ i. (i + 1) * j0 = i * j0 + j0 ⊦ (i + 1) * j0 +1 = i * j0 +1 + j0 +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ i. (i + 1) * j0 = i * j0 + j0 ⊦ (i + 1) * j0 = i * j0 + j0

Rule argument

Additional information

Used simplifier rules: succ-rsplit: ⊦ i * (j + 1) = i * j + i;% ⊦ i + j = i + i0 ↔ j = i0; (s)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ i +1 = i + 1; (s)