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Proof step 4 from proof succ-lsplit (previous step)

∀ i. (i + 1) * j0 = i * j0 + j0 ⊦ (i + 1) * j0 -1 = i * j0 -1 + j0 -1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ i. (i + 1) * j0 = i * j0 + j0 ⊦ (i + 1) * j0 -1 + 1 = i * j0 -1 + j0

Rule argument

Additional information

Used simplifier rules: ⊦ i +1 = i + 1; (s)% ⊦ i = j -1 ↔ i +1 = j; (s)%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ i + j -1 = (i + j)-1; (s)