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Proof step 11 from proof three (previous step)

i * j = 3, j < i, 1 < i, 0 < i, j ≤ 0 ⊦ j = 1, 3 ≤ i ∧ 1 < j

User applied rule cut formula

And obtained the following new goals

Proof step 12:
i * j = 3, 0 < i, 1 < i, j < i, j ≤ 0, i * j ≤ 0 ⊦ j = 1, 3 ≤ i ∧ 1 < j

Rule argument

fma: i * j ≤ 0

Additional information

Used simplifier rules: zero-le: ⊦ 0 < i → (i * j ≤ 0 ↔ j ≤ 0);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i ≤ j → (j < i ↔ false); (as) Used formulas: i * j ≤ 0