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Proof step 7 from proof zero-ge-add-02 (previous step)

(i + j) * j0 < j0, (i + j) * j0 < i + j, (i + j) * j0 < 0, 0 < j0, (i + j) * j0 + 1 < j0, 0 ≤ i + j ⊦ 0 < i + j

User applied rule cut formula

And obtained the following new goals

Proof step 8:
i + j = 0, (i + j) * j0 + 1 < j0, 0 < j0, (i + j) * j0 < 0, (i + j) * j0 < i + j, (i + j) * j0 < j0, 0 ≤ i + j ⊦ 0 < i + j

Rule argument

fma: i + j = 0

Additional information

Used simplifier rules: ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)% ⊦ i ≤ j → (j < i ↔ false); (as) Used formulas: i + j = 0