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Proof step 4 from proof zero-gr-add-02 (previous step)

0 < i1 * j + i0, j < 0, 0 ≤ i0, 0 ≤ i1, i0 ≤ i1 ⊦ i1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
j < 0, 0 < i1 * j + i0, 0 < i1, 0 ≤ i0, i0 ≤ i1 ⊦ i1 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)