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Proof step 3 from proof dec-int (previous step)

⊦ decode(encode(i)) = i, i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 ≤ i ⊦ decode(2 * i→n(i)) = i

Rule argument

Additional information

Used simplifier rules: enc-int-pos: ⊦ 0 ≤ i → encode(i) = 2 * i→n(i);%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)