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Proof step 14 from proof dec-nat (previous step)

2 * (n + 1) / 2 = m + 1 ⊦ n % 2 = 0, 2 * (n + 1) / 2 = 0, m = n, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
2 * (n + 1) / 2 = m + 1 ⊦ n % 2 = 0, m = n, n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = 1 ↔ m = 0 ∧ n = 1 ∨ n = 0 ∧ m = 1; (ws)%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + 1 ≠ 0; (s)% ⊦ m / 2 = 0 ↔ m = 0 ∨ m = 1; (s)% ⊦ 2 * m = 0 ↔ m = 0; (s)