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Proof step 4 from proof enc-zero-01 (previous step)

encode(i) = 0 ⊦ i = 0, 0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
2 * i→n(i) - 1 = 0, i < 0 ⊦ i = 0

Rule argument

Additional information

Used simplifier rules: enc-int-neg: ⊦ i < 0 → encode(i) = 2 * i→n(i) - 1;%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)