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Proof step 3 from proof enc-zero (previous step)

encode(encode(encode(i), encode(j))) = 0 ⊦ i = 0 ∧ j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: enc-zero-02: ⊦ encode(n) = 0 ↔ n = 0;%enc-zero-01: ⊦ encode(i) = 0 ↔ i = 0;% ⊦ encode(m, n) = 0 ↔ m = 0 ∧ n = 0; (ws)