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Proof step 2 from proof add-eq2pot-01 (
previous step
)
0 ≤ j, 0 ≤ i, 0 ≤ i0 ⊦ 2 * 2 ^ i = 2 ^ i0 + j ↔ j = 2 ^ i0 * (2 ^ (i + 1 - i0) - 1) ∧ i0 ≤ i + 1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
0 ≤ i0, 0 ≤ i, 0 ≤ j ⊦ 2 * 2 ^ i = 2 ^ i0 + j ↔ j = 2 ^ i0 * (2 ^ (i + 1 - i0) - 1) ∧ i0 ≤ i + 1
Rule argument
Additional information