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Proof step 14 from proof add-eq2pot (previous step)

(i2 + 1) * 2 ^ i0 = 2 ^ i0 + j, 2 ^ i1 = i2 + 1, 0 ≤ i1, 0 ≤ i1 + i0, 0 ≤ j, 0 ≤ i0 ⊦ (i2 + 1) * 2 ^ i0 - 2 ^ i0 = j, j = 2 ^ i0 * i2

User applied rule insert equation

And obtained the following new goals

Proof step 15:
(i2 + 1) * 2 ^ i0 = 2 ^ i0 + j, 2 ^ i1 = i2 + 1, 0 ≤ i0, 0 ≤ j, 0 ≤ i1 + i0, 0 ≤ i1 ⊦ 2 ^ i0 + j - 2 ^ i0 = j, j = 2 ^ i0 * i2

Rule argument

pos: left 1 flags:

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