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Proof step 70 from proof div-div-rec (previous step)

2 ^ i + j0 < i, j0 < 2 ^ i, j0 < 2 ^ i + i, 0 < i, abs(j0) < 2 ^ i, j0 < i, 2 * i1 < i, i1 < i, 2 ^ i * 2 * i1 + j0 < 0, 2 ^ i * (2 * (i1 + 1) - 1) + j0 < i, i1 ≤ 0, 0 ≤ i, j0 ≤ 0, 2 ^ i + j0 ≤ 0, j0 ≤ 2 ^ i, 2 ^ i * (2 * (i1 + 1) - 1) + j0 ≤ 0 ⊦ i1 = (2 ^ i * (2 * i1 - 1) + j0) / (2 ^ i * 2)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-abs name: Abs-neg seq: ⊦ j < 0 → abs(j) = 0 - j subst: [j] → [j0] flags: <all paths>

Additional information

Used simplifier rules: two-zero: ⊦ 0 ≤ j → 2 ^ j ≠ 0;%pot2-pos: ⊦ 0 < 2 ^ i ↔ 0 ≤ i;% ⊦ 0 - i = ~ i; (s)% ⊦ ~ i < j ↔ 0 < j + i; (s)% ⊦ i ≤ j → (j < i ↔ false); (as)% ⊦ ¬ j < 0 → abs(j) = j; (s)% ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ i ≤ j → (j ≤ i ↔ i = j); (s)% ⊦ i + 0 = i; (s)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%j ≠ 0, i0 ≠ 0 ⊦ (i * i0) / (j * i0) = i / j; (s)%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s) Used terms: j0