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Proof step 5 from proof div2-2pot-01 (previous step)

0 < 2, 0 < 2 ^ i, 0 ≤ i, 0 ≤ j ⊦ j / (2 * 2 ^ i) = j / 2 ^ (i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 < 2 ^ i, 0 ≤ i, 0 ≤ j ⊦ 2 * 2 ^ i = 2 ^ (i + 1), j / (2 * 2 ^ i) = j / 2 ^ (i + 1)

Rule argument

Additional information

Used simplifier rules: ⊦ 1 ≤ i ↔ 0 < i; (s)%neqf: ⊦ i / j ≠ i / i0 → j ≠ i0; (forward) from specification int-div%numlsf-02: ⊦ (* i) < j → i + 1 ≤ j; (forward) from specification int-abs