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Proof step 3 from proof div2-2pot-02 (previous step)

0 < j, 0 ≤ i ⊦ (i * 2 ^ j) / 2 = i * 2 ^ (j - 1)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
j = i0 + 1, 0 < j, 0 ≤ i ⊦ (i * 2 ^ j) / 2 = i * 2 ^ i0

Rule argument

spec: int-abs name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, 1, i0]

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, 1, i0