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Proof step 1 from proof eq-two (conclusion)

⊦ 0 ≤ i ∧ 0 ≤ j → (2 ^ i = 2 ^ j ↔ i = j)

System applied rule normalize

And obtained the following new goals

Proof step 2:
0 ≤ i, 0 ≤ j ⊦ 2 ^ i = 2 ^ j ↔ i = j

Rule argument

Additional information