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Proof step 2 from proof eqone (previous step)

i ^ j = 1, 0 ≤ j ⊦ abs(i) = 1, j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: Pot-pos: ⊦ 0 < i → j ^ i = j ^ i -1 * j;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ i * j = 1 ↔ abs(i) = 1 ∧ i = j; (ws)% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)