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Proof step 23 from proof equal-minus-one (previous step)

i + i ^ i0 = 0, abs(i ^ i0) = 1, 0 ≤ i0 ⊦ i = ~1, i = 0, i0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
i + i ^ i0 = 0, abs(i ^ i0) = 1, 0 < i0 ⊦ i = 0, i = ~1, i0 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)