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Proof step 26 from proof equal-minus-one (previous step)

i + i ^ i0 = 0, i ^ i0 = ~ i, abs(i ^ i0) = 1, 0 < i0, i < 0 ⊦ i = 0, i = ~1, i0 = 0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: discard

Additional information

Used simplifier rules: ⊦ abs(~ i) = abs(i); (s)% ⊦ i < 0 → abs(i) = ~ i; (s)% ⊦ ~ i = j ↔ i + j = 0; (s)% ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0; (s)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2% ⊦ ~ i + i = 0; (s)