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Proof step 47 from proof equal-minus-one (previous step)

i + i ^ ~(j + 1) = 0, abs(i ^ ~(j + 1)) = 1, j < 0 ⊦ i = ~1, i = 0, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 48:
i + i ^ ~(j + 1) = 0, i ^ ~(j + 1) = ~ i, abs(i ^ ~(j + 1)) = 1, j < 0 ⊦ i = 0, i = ~1, j = 0

Rule argument

fma: i ^ ~(j + 1) = ~ i

Additional information

Used simplifier rules: ⊦ ~ i = j ↔ i + j = 0; (s) Used formulas: i ^ ~(j + 1) = ~ i