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Proof step 50 from proof equal-minus-one (previous step)

abs(j) % 2 = 1, i = ~1, i ≠ 0 ∨ 0 ≤ j ⊦ i ^ j = ~1, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 51:
abs(j) % 2 = 1 ⊦ ~1 ^ j = ~1, j = 0

Rule argument

Additional information