~1 ^ j = ~1 ⊦ abs(j) % 2 = 1, j = 0, 0 < j
Used simplifier rules: minus-one-even: ⊦ 0 < j ∧ j % 2 = 0 → ~1 ^ j = 1;% ⊦ 0 < j → abs(j) = j; (s)% ⊦ 0 < i → (i % 2 = 1 ↔ i % 2 ≠ 0); (ss) Used formulas: 0 < j