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Proof step 12 from proof geom-mod (previous step)

(1 - i ^ i0) % (1 - i) = 0, 1 - i ^ i0 * i = (1 - i ^ i0) * i - (i - 1), 0 ≤ i0, ∀ j0, i. i→n(j0) < i→n(i0 + 1) → 0 ≤ j0 → (1 - i ^ j0) % (1 - i) = 0 ∨ i = 1 ⊦ (1 - i ^ i0 * i) % (1 - i) = 0, ~1 = i0, i = 1

User applied rule insert equation

And obtained the following new goals

Proof step 13:
(1 - i ^ i0) % (1 - i) = 0, 0 ≤ i0, ∀ j0, i. i→n(j0) < i→n(i0 + 1) → 0 ≤ j0 → (1 - i ^ j0) % (1 - i) = 0 ∨ i = 1 ⊦ ((1 - i ^ i0) * i - (i - 1)) % (1 - i) = 0, ~1 = i0, i = 1

Rule argument

pos: left 2 flags: discard

Proof step 12 from proof geom-mod (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information