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Proof step 5 from proof lemon2pot-02 (previous step)

n→i(m * n0 - 1) < n→i(m * n - 1), 2 ^ n→i(m * n0 - 1) + j0 < j, 1 < 2, n ≤ n0, j ≤ 2 ^ n→i(m * n - 1) + j0, 0 ≤ n→i(m * n0 - 1) ⊦ m = 0, n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ n→i(m) < n→i(n) ↔ m < n
Proof step 7:
1 < 2, 2 ^ n→i(m * n0 - 1) + j0 < j, m * n0 - 1 < m * n - 1, 0 ≤ n→i(m * n0 - 1), j ≤ 2 ^ n→i(m * n - 1) + j0, n ≤ n0 ⊦ m = 0, n = 0

Rule argument

spec: intnat name: nat2int-04 seq: ⊦ n→i(m) < n→i(n) ↔ m < n subst: [n, m] → [m * n - 1, m * n0 - 1] flags: <all paths>

Additional information

Used terms: m * n - 1, m * n0 - 1