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Proof step 5 from proof ls-pos-03 (previous step)

i ^ j < i0 ^ j, 0 < j, 0 ≤ i0, 0 ≤ i, i0 ≤ i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i ≤ i0 ∧ 0 ≤ i ∧ 0 ≤ j → ¬ i0 ^ j < i ^ j

Rule argument

spec: <toplevel> name: ls-pos-02 seq: ⊦ i ≤ i0 ∧ 0 ≤ i ∧ 0 ≤ j → ¬ i0 ^ j < i ^ j subst: [i, j, i0] → [i0, j, i] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s)% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i < j → ¬ j < i; (s) Used terms: i0, j, i