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Proof step 11 from proof ls-pos (previous step)

1 < i, 0 < i, j < j0, 0 ≤ j ⊦ i ^ j < i ^ j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
j < j0, 0 < i, 1 < i, 0 < j0, 0 ≤ j, i ^ j0 ≤ i ^ j ⊦

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)