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Proof step 2 from proof minus-odd (previous step)

0 < j, odd(j) ⊦ ~ i ^ j = ~(i ^ j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < j, odd(j) ⊦ i ^ j + ~ i ^ j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ ~ i = j ↔ i + j = 0; (s)