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Proof step 10 from proof mod-2pot (previous step)

~ abs(j) < 0, 0 < i ⊦ ~(abs(j) * 2 ^ i) % 2 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 11:
j ≠ 0 ⊦ ~ i % j = ~(i % j)
Proof step 12:
0 < i, ~ abs(j) < 0 ⊦ 2 = 0, ~((abs(j) * 2 ^ i) % 2) = 0

Rule argument

spec: int-div name: mod-neg-01 seq: j ≠ 0 ⊦ ~ i % j = ~(i % j) subst: [j, i] → [2, abs(j) * 2 ^ i] flags: <all paths>

Additional information

Used terms: 2, abs(j) * 2 ^ i