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Proof step 2 from proof mod-ngez-01 (previous step)

j < 0, 0 < i ⊦ 0 ≤ j % 2 ^ i ↔ j % 2 ^ i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < i, j < 0 ⊦ 0 ≤ j % 2 ^ i ↔ j % 2 ^ i = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs