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Proof step 6 from proof mod-two-ge (previous step)

0 ≤ j, j ≤ i, 0 ≤ i ⊦ 2 ^ i = 2 ^ i / 2 ^ j * 2 ^ j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ 0 ≤ i ∧ 0 ≤ j → 2 ^ i / 2 ^ j = 2 ^ (i - j)
Proof step 8:
j ≤ i, 0 ≤ i, 0 ≤ j ⊦ 2 ^ i = 2 ^ (i - j) * 2 ^ j

Rule argument

spec: <toplevel> name: div-twopot seq: ⊦ 0 ≤ i ∧ 0 ≤ j → 2 ^ i / 2 ^ j = 2 ^ (i - j) subst: [j, i] → [j, i] flags: <all paths>

Additional information

Used terms: j, i