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Proof step 3 from proof mod-two-ls (previous step)

i < j, 0 < j, 0 ≤ i ⊦ 2 ^ i % 2 ^ j = 2 ^ i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
0 < j, 0 ≤ i, i < j ⊦ i % j = i
Proof step 5:
0 < j, i < j, 0 ≤ i ⊦ 2 ^ i % 2 ^ j = 2 ^ i, 0 < 2 ^ j ∧ 0 ≤ 2 ^ i ∧ 2 ^ i < 2 ^ j

Rule argument

spec: int-div name: mod-zero-03 seq: 0 < j, 0 ≤ i, i < j ⊦ i % j = i subst: [j, i] → [2 ^ j, 2 ^ i] flags: <all paths>

Additional information

Used terms: 2 ^ j, 2 ^ i