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Proof step 12 from proof mod2-2pot-01 (previous step)

0 < 2 ^ i, 0 ≤ i, 0 ≤ i0 ⊦ (i0 % 2 ^ i * 2 + 1) / 2 = i0 % 2 ^ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
0 < 2 ^ i, 0 ≤ i, 0 ≤ i0 ⊦ (i0 % 2 ^ i * 2 + 1) / 2 = i0 % 2 ^ i

Rule argument

Additional information

Used simplifier rules: ⊦ 1 ≤ i ↔ 0 < i; (s)%numlsf-02: ⊦ (* i) < j → i + 1 ≤ j; (forward) from specification int-abs